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# -*- coding:utf-8 -*-
# author:gm
# mail: zhangguodong@igengmei.com
# datetime:2020/4/24 3:32 下午
# software: PyCharm
from functools import reduce
import copy
class Business(object):
def __init__(self):
pass
def sort(self):
pass
class Strategy(object):
def __init__(self):
pass
def run(self, documents):
return documents
class ScatterStrategy(Strategy):
def __init__(self):
self.name = "打散"
def strategy(self, documents, field_name, win_len=4):
"""
我们根据文档的某个字段将文档进行打乱，我们优先取值比较多的，
之后按照判断是否满足窗口大小
:param documents:
:param field_name:
:param win_len:多大的便宜内不出现重复值的数据
:return:
"""
ret_documents = []
ret_documents_idx = []
last_field_value_pointer = {}
field_dict = self.build_field_dict(documents, field_name)
while len(ret_documents_idx) < len(documents):
sorted_value = self.get_sorted_value(field_dict)
# print(ret_documents_idx, win_len, [documents[idx] for idx in ret_documents_idx])
is_append = self.ask(field_dict, sorted_value, win_len, last_field_value_pointer, ret_documents_idx)
if not is_append:
while win_len > 0:
win_len -= 1 # 如果窗口无法满足，那么采取贪心的策略
# print(ret_documents_idx, win_len, [documents[idx] for idx in ret_documents_idx])
is_append = self.ask(field_dict, sorted_value, win_len, last_field_value_pointer, ret_documents_idx)
if is_append:
break
for idx in ret_documents_idx:
ret_documents.append(documents[idx])
return ret_documents
# def remove_empty(self, field_dict):
# for value in field_dict:
# size = field_dict[value]["len"]
# if size <= 0:
# del field_dict[value]
def ask(self, field_dict, sorted_field, win_len=4, last_field_value_pointer={}, ret_documents_idx=[]):
"""
轮询填充数据
:param field_dict:分组后的items数据
:param sorted_field:根据数量排序后的值
:param win_len:窗口大小
:param last_field_value_pointer:存放着类别当前存储到的offset
:param ret_documents_idx:返回数据的下标
:return:
"""
is_append = False
for value in sorted_field:
# 没有取过的话直接取
if value not in last_field_value_pointer:
is_append = True
# 记录当前类别放置的offset
last_field_value_pointer[value] = len(ret_documents_idx)
current_value = field_dict[value]["items"].pop(0)
ret_documents_idx.append(current_value)
field_dict[value]["len"] -= 1
break
else:
# 取过的话，我们获取上次放置的offset，然后看窗口大小是否合适
current_idx = last_field_value_pointer[value]
current_value = len(ret_documents_idx)
if current_value - current_idx >= win_len: # 窗口大小进行判断
is_append = True
ret_documents_idx.append(field_dict[value]["items"].pop(0))
last_field_value_pointer[value] = current_value
field_dict[value]["len"] -= 1
break
else:
continue
return is_append
def get_sorted_value(self, field_dict):
"""
按照值的数量进行排序，我们优先取值比较多的
:param field_dict:
:return:
"""
ret = sorted(field_dict.keys(), key=lambda x: field_dict[x]["len"], reverse=True)
ret = filter(lambda x: field_dict[x]["len"] > 0, ret)
return list(ret)
def build_field_dict(self, documents, field_name):
"""
将文档根据某个字段的值进行归类，字段可以是类目，机构等等
:param documents:
:param field_name:
:return:
"""
ret = {}
for idx, document in enumerate(documents):
if field_name in document:
value = document[field_name]
if value in ret:
ret[value]["items"].append(idx)
ret[value]["len"] += 1
else:
ret[value] = {
"items": [idx],
"len": 1
}
else:
if "empty_value" in ret:
ret["empty_value"]["items"].append(idx)
ret["empty_value"]["len"] += 1
else:
ret["empty_value"] = {
"items": [idx],
"len": 1
}
return ret
class HierarchyStrategy(Strategy):
def __init__(self):
pass
def strategy(self, documents, fields):
"""
:param documents:
:param fields:{"is_common_city":[1,0],"score":[1500,1000,800]}
:return:
"""
result = [documents]
for field_name in fields:
tmp = []
for item in result:
for value in fields[field_name]:
tmp.append(list(filter( lambda x: x[field_name] == value,item)))
result = tmp
return result
if __name__ == "__main__":
# documents = [{"a": 0}, {"a": 1}, {"a": 1}, {"a": 1}, {"a": 2}, {"a": 0}, {"a": 0}, {"a": 3}, {"a": 3}]
s = ScatterStrategy()
# print(s.strategy(documents, "a"))
documents = [{"is_common_city": 1, "score": 1500, "merchant_id": 1111, "is_promote": True, "id": 1},
{"is_common_city": 1, "score": 1500, "merchant_id": 1111, "is_promote": True, "id": 11},
{"is_common_city": 1, "score": 1500, "merchant_id": 1111, "is_promote": True, "id": 12},
{"is_common_city": 1, "score": 1500, "merchant_id": 1112, "is_promote": True, "id": 13},
{"is_common_city": 1, "score": 1500, "merchant_id": 1111, "is_promote": True, "id": 14},
{"is_common_city": 1, "score": 1500, "merchant_id": 1112, "is_promote": True, "id": 15},
{"is_common_city": 1, "score": 1500, "merchant_id": 1111, "is_promote": True, "id": 1},
{"is_common_city": 1, "score": 1500, "merchant_id": 1112, "is_promote": False, "id": 2},
{"is_common_city": 1, "score": 1500, "merchant_id": 1111, "is_promote": True, "id": 3},
{"is_common_city": 1, "score": 1000, "merchant_id": 1113, "is_promote": False, "id": 4},
{"is_common_city": 1, "score": 1000, "merchant_id": 1111, "is_promote": True, "id": 5},
{"is_common_city": 0, "score": 1500, "merchant_id": 1114, "is_promote": True, "id": 6},
{"is_common_city": 0, "score": 1500, "merchant_id": 1114, "is_promote": False, "id": 7},
{"is_common_city": 0, "score": 1000, "merchant_id": 1113, "is_promote": True, "id": 8},
{"is_common_city": 0, "score": 1000, "merchant_id": 1113, "is_promote": False, "id": 9},
{"is_common_city": 0, "score": 1500, "merchant_id": 1112, "is_promote": True, "id": 10}]
model = HierarchyStrategy()
result = model.strategy(documents,
fields={"is_common_city": [1, 0], "score": [1500, 1000, 0], "is_promote": [True, False]})
# print(result)
# print(len(list(filter(lambda x:x!=[],result))))
# print(s.strategy(documents, "merchant_id"))
for item in list(filter(lambda x:x!=[],result)):
print(s.strategy(item,"merchant_id"))